Description :

In a string s of lowercase letters, these letters form consecutive groups of the same character.

For example, a string like s = "abbxxxxzyy" has the groups "a", "bb", "xxxx", "z", and "yy".

A group is identified by an interval [start, end], where start and end denote the start and end indices (inclusive) of the group. In the above example, "xxxx" has the interval [3,6].

A group is considered large if it has 3 or more characters.

Return the intervals of every large group sorted in increasing order by start index.

Example 1:

Input: s = "abbxxxxzzy"
Output: [[3,6]]
Explanation: "xxxx" is the only large group with start index 3 and end index 6.
Example 2:

Input: s = "abc"
Output: []
Explanation: We have groups "a", "b", and "c", none of which are large groups.
Example 3:

Input: s = "abcdddeeeeaabbbcd"
Output: [[3,5],[6,9],[12,14]]
Explanation: The large groups are "ddd", "eeee", and "bbb".
Example 4:

Input: s = "aba"
Output: []

Constraints:

• 1 <= s.length <= 1000
• s contains lower-case English letters only.

Remark : Review # Sunday Funday # Let me Relax
status : PASS

class Solution:
    
    def largeGroupPositions(self, s: str) -> List[List[int]]:
        ansList = []
        cnt = 1
        start = 0
        end = (len(s) -1)
        flag = 0
        for i in range(len(s)):
                
                
                if i>0 and s[i-1]==s[i]:
                    print("c1:"+s[i])
                    cnt = cnt + 1
                    if i==(len(s)-1) and (cnt>=3):
                        flag = 1
                        ansList.append([start,i])
                else:
                    if cnt >=3 :
                        flag = 1
                        print("AnsCnt:"+str(cnt))
                        ansList.append([start,i-1])    
                    print("c2"+s[i])                        
                    start = i    
                    cnt = 1
   
        if flag == 0:
            return []
        print(ansList)
        return ansList